Class 10 Maths 1 Statistics Practice Set 6.5 Solutions | Maharashtra Board
Class 10 Maths 1 – Statistics
Practice Set 6.5 Solutions
Introduction
Welcome to Rukmini Classes! In this lesson, we provide the complete solutions to Practice Set 6.5 from Chapter 6, Statistics, of Class 10 Mathematics 1, Maharashtra State Board.
This practice set covers frequency polygons, class-marks, frequencies, and the graphical representation of statistical data.
The solutions are presented in a clear and easy-to-understand format to help students understand the concepts, practise graph drawing, and prepare effectively for the SSC Board Examination.
Learn • Practise • Prepare for Exams
Practice Set 6.5 – Solutions
Q.1. Observe the frequency polygon and answer the following questions.
Answer: The class 60–70 has the maximum number of students, i.e., 60 students.
Answer: The classes having zero frequency are 20–30 and 90–100.
Answer: The class-mark is 55.
Answer:
- Lower class limit = 80
- Upper class limit = 90
Answer: There are 15 students in the class 80–90.
Q.2. Show the following data by a frequency polygon.
Given data:
| Electricity Bill (₹) | Families |
|---|---|
| 0–200 | 240 |
| 200–400 | 300 |
| 400–600 | 450 |
| 600–800 | 350 |
| 800–1000 | 160 |
Solution:
Step 1: Calculate the class-marks.
Class-mark = (Lower class limit + Upper class limit) ÷ 2
| Class Interval | Class-mark (x) | Frequency (y) |
|---|---|---|
| 0–200 | 100 | 240 |
| 200–400 | 300 | 300 |
| 400–600 | 500 | 450 |
| 600–800 | 700 | 350 |
| 800–1000 | 900 | 160 |
Step 2: Plot the points:
(100, 240), (300, 300), (500, 450), (700, 350), (900, 160)
Step 3: Add the zero-frequency points (-100, 0) and (1100, 0) to close the frequency polygon.
Step 4: Join all the plotted points in order using straight lines.
- X-axis: Class-marks of electricity bills
- Y-axis: Number of families
Q.3. Draw a frequency polygon from the following table.
| Result (Percentage) | No. of Students |
|---|---|
| 30–40 | 7 |
| 40–50 | 33 |
| 50–60 | 45 |
| 60–70 | 65 |
| 70–80 | 47 |
| 80–90 | 18 |
| 90–100 | 5 |
Solution:
Step 1: Calculate the class-marks.
Class-mark = (Lower class limit + Upper class limit) ÷ 2
| Class Interval | Class-mark (x) | Frequency (y) |
|---|---|---|
| 30–40 | 35 | 7 |
| 40–50 | 45 | 33 |
| 50–60 | 55 | 45 |
| 60–70 | 65 | 65 |
| 70–80 | 75 | 47 |
| 80–90 | 85 | 18 |
| 90–100 | 95 | 5 |
Step 2: Plot the points:
(35, 7), (45, 33), (55, 45), (65, 65), (75, 47), (85, 18), (95, 5)
Step 3: Add the zero-frequency points (25, 0) and (105, 0) to close the polygon.
Step 4: Join all the plotted points in order using straight lines to obtain the frequency polygon.
- X-axis: Class-marks of percentages
- Y-axis: Number of students



Comments
Post a Comment